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Coulomb’s Law and Law of Universal Gravitation

	Given: $r_e=6.38\cdot^6m$ $r_s=3.00\cdot10^4$ m $m_e=5.97\cdot10^{24}Kg$ G= $6.67\cdot10^{-11}\frac{N\cdotm^2}{Kg^2}$
	Find: orbital speed v=? orbital period T=?

V= $\sqrt{\frac{G\cdot m_e}{r}}$
r= $6.7\cdot 10^6 m + 3.00 \cdot 10^4 m = 6.41 \cdot 10^6 m$
V= $\sqrt{\frac{(6.67 \cdot 10^{-11} \frac{N \cdot m^2}{Kg^2} )(5.97 \cdot 10^{24}Kg)(1)}{6.41 \cdot 10^6 m}$
V= $7.88 \cdot 10^3 \frac{m}{s}$
T= $2\pi \cdot \sqrt{\frac{r^3}{6\cdot m_e}}$
T= $2 \pi \cdot \sqrt{\frac{(6.41 \cdot 10^3 m)^3}{(6.67 \cdot 10^{-11} \frac{N \cdot m^2}{Kg^2})(5.97 \cdot 10^{24} Kg)(1)}}$
T=5110s=852 min = 1.4 hours