Production of Electromagnetic Waves


Example: An X-Ray machine, such as the one used in a medical office operates by accelerating electrons with a very large potential difference (about 25,000V). These electrons are accelerated into a positively charged plate. As the electrons are very excited and moving very quickly, their impact on the plate results in a large energy release. This energy is released in the form of high energy photons otherwise known as X-Rays. Suppose that a single electron were to release all of its energy among 5 photons how much energy would each photon have?


Draw a picture Known Find
q_e=-1.6\cdot 10^{-19}C
\DeltaV = 25,000V
N=5 photons
Energy per photon

Base Equation \DeltaE=(q_e)(\DeltaV)
(-1.6 \cdot 10^{19} C)(25,000 V) = 4.0 \cdot 10^{-15}J
Divide the total energy by the number of photons in order to determine the energy per photon
E_p=\frac{\Delta E}{N}
\frac{4.0 \cdot 10^{-15} J}{5 photons} = 8 \cdot 10^{-16} \frac{J}{Photon}