Solving Word Problems Involving Applications of Exponential Functions to Growth and Decay

The population of a certain county can be modeled by the equation:

P(t)=50e^{0.02t}

Where P is the population in millions, t is the number of years since 1900. Find when the population is 100 million, 200 million, and 400 million. What do you notice about these time periods?

100 million

\frac{100,000,000}{50}=\frac{50e^{0.02t}}{50}

2,000,000=e^{0.02t}

ln(2,000,000)=ln(e^{0.02t})

\frac{14.51}{0.02}=\frac{0.02t}{0.02}

725.43=t

200 million

200,000,000=50e^{0.02t}

4,000,000=e^{0.02t}

ln(4,000,000)=ln(e^{0.02t})

15.20=0.02t

760.09=t

400 million

ln(8,000,000)=ln(e^{0.02t})

t=794.75

794.75-760.09=34.66\ yrs

760.09-725.43=34.66\ yrs

 

Population doubles every 34.66 yrs