Deck of Cards Problem

In a standard deck of playing cards, what is the probability of drawing a jack?

52 cards        4 Jacks\frac{4}{52}=\frac{1}{13}
If two cards are drawn successively, without replacement, what is the probability of drawing two aces?

P(1^{st} Ace)=\frac{4}{52}= \frac{1}{13}

P(2^{nd} Ace)=\frac{3}{51}= \frac{1}{17}

P(both Aces) = \frac{1}{13} \cdot \frac{3}{51}= \frac{3}{13 \cdot 51}=\frac{3}{663}=\frac{1}{221}